The sum of the series 1 + (1 + 2 + 4) + (4 + 6 + 9) + (9 + 12 + 16) + ....... + (361 + 380 + 400) is ?

Question

The sum of the series  1 + (1 + 2 + 4) + (4 + 6 + 9) + (9 + 12 + 16) + ....... + (361 + 380 + 400) is ?

anonymous · Answer

Use calculator and start adding..

ha ha hah a..

experimentx · Answer

find the pattern
 (1 + 2 + 4) + (4 + 6 + 9) + (9 + 12 + 16) +
1                         2                      3

anonymous · Answer

Does this Have a pattern?? i am unable

anonymous · Answer

Of course this is a pattern...

anonymous · Answer

1 + (7) + (19) + (37)

   6        12       18        24       30 like that..

anonymous · Answer

Every times the number is increasing in multiples of 6..

anonymous · Answer

@Yahoo! 
water in eyes got it exactly right. . .
its a.p with d=6

experimentx · Answer

what could be the next term in the series?

anonymous · Answer

37 + 24 = 61

experimentx · Answer

(16 + 20 + 25) + (25 + 30 + 36) + ...

experimentx · Answer

of you look at it ... this is just sum of 3 times n^2 + normal arithmetic series

anonymous · Answer

61 + 30 = 91

experimentx · Answer

and you know n^2 = n(n+1)(2n+1)/3 ... just do it that way.

anonymous · Answer

by 6 i guess..

anonymous · Answer

yes /6

experimentx · Answer

and by the way 19^2 = 361 ... can you do it?

anonymous · Answer

@experimentX  i did nt understand

anonymous · Answer

we figured out the pattern  next??

anonymous · Answer

@ yahoo yes we have
in a.p. a=1 by d=6
water in eyes got it perfect

experimentx · Answer

|dw:1343843229554:dw|