Question

2x^2-15x-8

Answer 1

\[\large{2x^2-15x-8}\]

You have to factorize this?

Answer 2

yes

Answer 3

ok so : :
\[\large{2x^2+16x-1x-8}\]
\[\large{2x(x+8)-1(x+8)}\]

Answer 4

try to take (x+8) common

Answer 5

how do you do that??

Answer 6

need help @Ganpat

Answer 7

can u continue from wher mathslover stopped ??

Answer 8

wht z da step u dnt understnd?

Answer 9

2x(x+8)−1(x+8)

what common can u take from this ??

Answer 10

@broderick365 : der ??

Answer 11

8

Answer 12

no no..

2x(x+8)−1(x+8)
(x+8) (2x -1)..

x+8 .. should be common right ??

Answer 13

@broderick365 see what is the common term there. is it 8 or ??

Answer 14

yehp

Answer 15

i thought u understood in previous problem. .. :(

Answer 16

not really

Answer 17

ha ha, u shd have told me.. :D..

anyways.. now do u understand ??

Answer 18

so the answer is 2x+1 x+8

Answer 19

noo..

(x+8) (2x -1) = 0

equate each bracket to 0, and find x.. u will get 2 values..

Answer 20

how do you do that??

Answer 21

x+8 = 0

and 2x -1 = 0

now, can u simplify ??

Answer 22

so the answer would be -8

Answer 23

one answer is x = -8..

and other is x = 1/2..