Question

Solve for x^2.
x^4-4X^2+2=0.
Please show work.

Answer 1

Do you mean solve for x?

Answer 2

No like \[x^{2}\]

Answer 3

take x^2 = t , then
\[x^{4}-4x^{2}+2 = t^{2}-4t+2=0\]
now solve the eqn
\[t^{2}-4t+2\] for t

Answer 4

well you can let z = x^2

So z^2 = x^4, which means

x^4-4x^2+2=0

becomes

z^2-4z+2=0

Now solve for z

Answer 5

@floridagirl150 got it?

Answer 6

i'm still kinda confused but that helps me get started. Thanks :)