Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

Look at the figure below. Which conclusion is most likely correct about the figure? The length of side AC is equal to 10 cm. The length of side AC is equal to 15 cm. The length of side AC is equal to 35 cm. The length of side AC is equal to 20 cm.

OpenStudy (anonymous):

OpenStudy (anonymous):

try cosine law or sine law?

OpenStudy (valpey):

No, don't do any trigonometry. Just eyeball it. Should it be longer or shorter than CD?

OpenStudy (anonymous):

@Valpey i dont know lol

OpenStudy (valpey):

Look at AC as compared to CD. The only difference between the triangle on top and the triangle on bottom is the angle on the left. Which is bigger, 47 degrees or 40 degrees?

OpenStudy (anonymous):

The length of side AC is equal to 10 cm. maybe ?

OpenStudy (anonymous):

they look the same to me lol

OpenStudy (anonymous):

so would it be 10 cm?

OpenStudy (anonymous):

it should shorter i think , because it has lower degrees than another both of them BA = BD = 20cm

OpenStudy (anonymous):

so either 10 or 20 cm?

OpenStudy (anonymous):

i mean , they first leg both 20 cm BA=BD .. and they have different degree , the first one 40 degree , the second one 47 degree which has 15 as another leg, so I assume hat the first one 40 degree triangle has lower leg ( AC ) than DC

OpenStudy (anonymous):

so lost lmao

OpenStudy (anonymous):

try to look carefully ;)

OpenStudy (anonymous):

@KingGeorge can you help

OpenStudy (anonymous):

@Hero ?

hero (hero):

Hint: Use law of sines

hero (hero):

Or "eyeball" it as suggested above.

hero (hero):

@47 degrees, CD = 15 @40 degrees, AC = something less than 15

OpenStudy (anonymous):

10

hero (hero):

See how easy that is? 40 < 47 therefore AC < CD

OpenStudy (anonymous):

yea lol

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!