Question

solve. 10x^4-11x^2+3=0

Answer 1

let x^2 = y, then your equation results to:
\[10y ^{2} -11y+3 = 0\]
is that familiar?

Answer 2

\[10y ^{2}-11y+3=0\]
\[10y-5y-6y+3=0\]
\[5y(\[x= \pm \sqrt{3/5} \]2y-1)-3(2y-1)=0\]
\[(5y-3)(2y-1) =0\]
then :
\[5y-3=0 or 2y-1=0\]
therefore y =3/5 or y=1/2
but remember y= x^2
this means :
\[x ^{2} = 3/5\]
and
\[x ^{2} = 1/2\]
implying :
\[x= \pm \sqrt{3/5}\]
and
\[x= \pm \sqrt{1/2}\]
question?

Answer 3

Thats what I got. thatnks :)