Question

What values for q (0 £ q < 2p) satisfy the equation?

2√2sinq + 2 = 0

Answer 1

\[2\sqrt{2}\sin(q)+2=0\]

Answer 2

\[2\sqrt{2}\sin(q)=-2\]
\[\sqrt{2}\sin(q)=-1\]
\[\sin(q)=-\frac{1}{\sqrt{2}}=-\frac{\sqrt{2}}{2}\]

Answer 3

now what you need is a number \(q\) with
\[ \sin(q)=-\frac{\sqrt{2}}{2}\]

Answer 4

find it on the attached cheat sheet
that is, find where the second coordinate is \(-\frac{\sqrt{2}}{2}\)
the angle will be your answer

Answer 5

that wasn't one of my answers.