can someone help me figure this problem out step by step?: x^2+2x-15=0
\[x^{2}+2x-15=0 \] \[(x+5)(x-3)\] This is the simplified way to write this problem.
So much for the "step by step"
@moody
what would you have to do after putting it in the simplified way?
what would you have to do after putting it in the simplified way?
What are they asking you to do with this problem?
solve it
Step by Step would essentially be to factor by grouping to show the logical steps. For example: \(x^2 + 2x - 15 = 0\) You would split the middle term to get: \(x^2 + 5x - 3x - 15 = 0\) Then factor the first two terms and the last two terms to get: \(x(x+5) - 3(x+5) = 0\) Then factor out x + 5 to get: \((x+5)(x-3) = 0\) Then finish solving from there. The complete steps required two find the middle two terms (without guessing) are much longer.
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