Question

Did I do this Algebra problem correctly?

(2a^4b)^3/24b^5

I put a^12/3b^2

Answer 1

yes you did

Answer 2

\[\huge \frac{(2a^4b)^3}{24b^5} \implies \frac{8a^{12} b^3}{24b^5} \implies \frac{a^{12}}{3b^2}\]

Answer 3

yes u did
see here
http://www.wolframalpha.com/input/?i=%282a%5E4b%29%5E3%2F24b%5E5

Answer 4

MOre fun! :)

28m^-4n^6/4mn^-2p^-2

Is it 7n^8/m^5p^2

Answer 5

uhhh doesnt sound right... p^2 should be at the top

Answer 6

\[\huge \frac{28m^{-4} n^6}{4mn^{-2} p^{-2}} \implies \frac{28n^6 n^2 p^2}{4m^4 m}\]
see?

Answer 7

Okay..

7n^4p^2/m^3 We good? :)

Answer 8

yes its correct (7 n^4)/(m^3 p^2)

Answer 9

lol i got confused...

Answer 10

m^3 is still wrong

Answer 11

So... am I write? :P

Answer 12

by doing this (28×n^6/4×m/n^2)/(m^4 p^2)

Answer 13

*right

Answer 14

7n^4p^2/m^3 We good? :)

Answer 15

\[m^4 \times m \ne m^3\]

Answer 16

you're almost right except for that m^3

Answer 17

hint:
\[\huge m^4 \times m = m^{4+1}\]

Answer 18

M^5 :P

Answer 19

right! \[\huge \frac{7n^8 p^2}{m^5}\]

Answer 20

MOre fun!

20m-4n^5/2mn^-2p^-3

is it 10n^3p^3/m^3

Answer 21

lol you're pushing it arent you =))

anyway if you meant \[\huge \frac{20m^{-4}n^5}{2mn^{-2}p^{-3}}\]
then you're wrong

Answer 22

change it into positive exponents first so you wont get confused

Answer 23

your exponents for m and n are wrong

Answer 24

is n7 and m5?

Answer 25

And yes, yes I am. :)

Answer 26

yup \[\huge \frac{10n^7 p^3}{m^5}\]

Answer 27

THANK YOU! :D

Answer 28

welcome :D

Answer 29

OH my god, this next problem is like, impossible. You ready?

Answer 30

lol lay it on me

Answer 31

Volume of sphere = pir^2h