Question

Didn't have an answer for this problem that needed confirmation because I'm having trouble with it. Please help! Click attached

Answer 1

Hint: Use simple algebra to reduce the equation.

Answer 2

x = Arcsec 2 :)

Answer 3

\(3(\sec x - 1) = 5 - \sec x\)
\(3 \sec x - 3 = 5 - \sec x \)
\(3 \sec x + \sec x = 5 + 3 \)
\(4 \sec x = 8\)
\(\sec x = \frac{8}{4}\)

Answer 4

You can try letting z = sec(x)

So

3(sec(x) - 1) = 5 - sec(x)

becomes

3(z-1) = 5 - z

Now solve for z

Answer 5

Your last step in solving for z will be your second to last step in solving for x

Answer 6

Go from there