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OpenStudy (anonymous):
Which of the following is the formula for the geometric sequence?5, 25, 125, 250, …
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OpenStudy (anonymous):
please help me someone
OpenStudy (unklerhaukus):
what factor does the next term in the sequence have compared the the term before it
OpenStudy (anonymous):
its times 5
OpenStudy (unklerhaukus):
good ,
OpenStudy (anonymous):
so what would be the formula
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OpenStudy (unklerhaukus):
so the first term = 5
the second is 5x5 = 5^2
the third is 5x5x5 = 5^3
OpenStudy (unklerhaukus):
whats the nth term?
OpenStudy (anonymous):
i not sure
OpenStudy (unklerhaukus):
well when n=1 the term is 5
when n=2 the term is 5^2
when n=3 the term is 5^3
when n=n the term is ......?
OpenStudy (anonymous):
5^9
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OpenStudy (anonymous):
so is the formula
an=5(5)^n − 1
OpenStudy (unklerhaukus):
why do you have two fives in you equation?
OpenStudy (unklerhaukus):
oh wait i see now
OpenStudy (unklerhaukus):
yeah you could have that
OpenStudy (anonymous):
ya
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OpenStudy (unklerhaukus):
\[a_n=5(5)^{n − 1}\]
\[a_1=5(5)^{1 − 1}=5(5)^0=5\times1=5\]\[a_2=5(5)^{2 − 1}=5(5)^1=5\times5=25\]
it works
OpenStudy (unklerhaukus):
but you could simplify it
\[a_n=5(5)^{n − 1}=5^1\times5^{n-1}=5^{n-1+1}=5^n\]
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