Question

How do i solve this?

Answer 1

perpendicular

Answer 2

12x+4y=16..............1
27x+9y=40..........2

from equation 1
12x=16-4y
x=16-4y/12 now put the value of x in 2nd equatipn.

Answer 3

i need to know how to solve.. not just the answer @best.shakir

Answer 4

ok so just use substitution ?

Answer 5

yes

Answer 6

emily, question is asking to tell whther the two lines given are
"parallel" or "perpendicular" or "neither"

right ?

Answer 7

find slope of each line,

if they are equal => lines are parallel

Answer 8

u know how to find slope ?

Answer 9

Yes, its -3 correct? (sorry i was afk)

Answer 10

or are they perpendicular?

Answer 11

np

Answer 12

find slope for both lines

Answer 13

both u getting -3 ?

Answer 14

yes

Answer 15

if both slopes are equal, they are parallel

Answer 16

ok, i get it now. Havent done that kind of problem in so long, i forgot.

Answer 17

i have another, different tho, you have time?

Answer 18

yeah np ;)

sure post... .

Answer 19

and for perpendicular lines,

if you multiply both slopes, you will get -1

Answer 20

-4x-5y = -15 ----(1)
2x + 2y = 6 ------(2)

Answer 21

multiply second equation with 2

Answer 22

-4x-5y = -15 ----(1)
4x + 4y = 12 ------(2)

Answer 23

add both equations

Answer 24

4x cancels

Answer 25

-5y+4y = -15+12

Answer 26

-y = -3
y=3

Answer 27

ok , i knew that i had to do that.. i was just second guessing my self this is most stuff we learned in the beginning.

Answer 28

put y=3 in second equation,

2x + 2(3) = 6
2x + 6 = 6
2x = 0
x= 0

Answer 29

you refreshing algebra I is it...

Answer 30

nice :)

Answer 31

yes, we have our final exam tomorrow :), have time for a word problem?

Answer 32

i can post new question so i can give u medals

Answer 33

wow you will do best :) good luck :))

Answer 34

np... u already gave me so many medals... so its okay lol

Answer 35

haha ok :3

Answer 36

anyways... post it new... so that others can also have a look n help

Answer 37

oh ok. u already posted... let me c

Answer 38

Easy..

Answer 39

time = distance/speed

Answer 40

u know this relation right ?

Answer 41

oh . see? i forget the simple stuff

Answer 42

we need to find speed of Chuck,
lets call that x

Answer 43

time travelled by Chuck = distance /speed = 66/x -------- (1)

Answer 44

Dana's speed is 6mph less than chuck, so dana speed = x-6

time travelled by Dana = distance/speed = 54/(x-6) -----------(2)

Answer 45

since time travelled by both Chuck & Dana is same,

(1) = (2)

Answer 46

\(\frac{66}{x} = \frac{54}{x-6}\)

Answer 47

\(66(x-6) = 54x\)

66x- 396 = 54x

12x = 396

x = 33

Answer 48

Chuck travels at 33 mph

Answer 49

ok, sweet. thanks . you're really helping me out. im just trying to make sure i fully understand for tommorow. i will open a new question now :)

Answer 50

ok ty.. :)