Question

factorize : a(sqrt)2+b(sqrt)2-2(ab-ac+bc)

Answer 1

@Neemo can u help....

Answer 2

\[a ^{2}+b ^{2}-2(ab-ac+bc)\]

Answer 3

@Neemo

Answer 4

now ! It's clear !
\[-2(ab-ac+bc)=\text{???}\]
can you re-type that without using "(" ")"

Answer 5

\[-2ab+2ac-2bc\]

Answer 6

Good ! Can you re-type all of \[a^2+b^2-2(ab-ac+bc)\] without using "("("

Answer 7

\[a ^{2}+b ^{2}-2ab+2ac-2bc\]

Answer 8

\[\color{red}{a^2+b^2-2ab}+\color{green}{2}a \color{green}{c}-\color{green}{2}b \color{green}{c}\]

Answer 9

does the "red one" mean something to you ?

Answer 10

\[a ^{2}-2ab+b ^{2}= (a-b)^{2}\]

Answer 11

good ! Do you see the common factor "in the rest" of the expression !

Answer 12

neemo's explanation is good
u can see here to understand more
http://www.wolframalpha.com/input/?i=a%28sqrt%292%2Bb%28sqrt%292-2%28ab-ac%2Bbc%29

Answer 13

Thank you Shakir !! Can you @basith ?

Answer 14

i dont understand anythin in wolfram......it ill be better if u explained..

Answer 15

just Focus basith ! \[\color{green}{2}b \color{green}{c}-\color{green}{2}a \color{green}{c}\]=??????

Answer 16

\[2c(b-a)\]

Answer 17

its 2ac-2bc...so= 2c(a-b)

Answer 18

then @Neemo ????????

Answer 19

yes ! just re-type the whole expression !

Answer 20

(a-b)(a-b) + 2c(a-b)

Answer 21

then??????'

Answer 22

you don't see anything :) ? the common factor....

Answer 23

(a-b) [a-b+2c].....right????

Answer 24

yeeaaah ! Good ! Very good !

Answer 25

thnx 4 the help

Answer 26

yw ! :)