What is true about the solutions of a quadratic equation when the radicand in the quadratic formula is negative?
No real solutions
Two identical rational solutions
Two different rational solutions
Two irrational solutions
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OpenStudy (lgbasallote):
hint:
b^2 -4ac > 0 means 2 different solution
b^2 -4ac = 0 means 2 identical solutions
b^2 - 4ac < 0 means no real solutions
does that help?
OpenStudy (anonymous):
a little, but what is a radicand?
OpenStudy (lgbasallote):
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
the radicand is the expression *in* the square root..in other worrds b^2 -4ac
OpenStudy (anonymous):
ohhh okay thanks!
OpenStudy (lgbasallote):
welcome
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OpenStudy (anonymous):
so...would it be two different rational
OpenStudy (lgbasallote):
why do you say that?
OpenStudy (lgbasallote):
if the radicand is negative...then is it greater than 0?equal to 0? or less than 0?
OpenStudy (anonymous):
less than zero
OpenStudy (anonymous):
ohhh aha forgot about your hint
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