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OpenStudy (anonymous):
help
OpenStudy (ghazi):
just substitute the values of x and y ..you can plot the graph
OpenStudy (ghazi):
let's say (1,2),(3,4),(2,2) so at different coordinates you can draw a whole line
OpenStudy (anonymous):
so how would I do that
OpenStudy (ghazi):
for every value of X find the value of Y and plot it on graph..
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OpenStudy (ghazi):
like consider the equation 3X+Y=0 now for the value of X=1 you will get Y= -4 in this way you can have set of points on graph paper for each pair of X,Y and you can draw line
OpenStudy (anonymous):
I do not do well i graphing
OpenStudy (ghazi):
so basically you need a solution?
OpenStudy (anonymous):
yes
OpenStudy (ghazi):
wait a min
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OpenStudy (anonymous):
are you stll there
OpenStudy (anonymous):
hello
OpenStudy (ghazi):
yea it's done i am drawing graph wait
OpenStudy (anonymous):
1st find x inercept n y intercept 2 draw graph of each line
next find lines intersection point by solving them
plot that points 2 get graph
OpenStudy (ghazi):
for the equation 3X+Y=0, Y=-3X, now at X=1 Y= -3 and at X=2,Y=-6 similarly you can find values for second equation ...therefore you'll get this...|dw:1343929302476:dw|