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solve:2(x – 3) ≥ 5 – (x + 3)
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open up the parenthesis: \[2x-6 \ge 5-x-3\] can you proceed from here?
no :/
OK, first get the like terms to one side, we can put the unknowns(those with x) on the LHS and the knowns on the RHS, such that: \[2x+x \ge 5-3+6\] got it up to there?
I think I did it wrong, I got 2.67
you're somehow right, but this is an inequality, so the answer should be: \[x \ge 2.67\]
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Cool! Thanks.
\[3x \ge 8\] divide all through by 3 \[x \ge 2.67\]
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