Write the equation of the line in slope-intercept form that passes through the point (3, -2) and has a slope of 2.

Question

lgbasallote · Answer

use point slope formula $$y-y_1 = m(x-x_1)$$
does that help?

lgbasallote · Answer

or do you need more help?

anonymous · Answer

yes please

zzr0ck3r · Answer

y = mx+b
we know m
y = 2x+b now plug in the values
-2 = 2(3) + b
-2 = 6+b
-2-6 = b
b = -8
so now what is the equation?

lgbasallote · Answer

in my equation..you just plug in directly what you have
m = slope = 2
x1 is the x coordinate = 3
y1 is the y coordinate = -2

so plug it in

$$y - y_1 = m(x-x_1)$$
$$y-(-2) = 2(x-4)$$
now simplify that equation to get your equation of the line

zzr0ck3r · Answer

im pretty sure @lgbasallote had a typo and meant y-(-2) = 2(x-3)... just to let you know.

lgbasallote · Answer

uhh yeah thanks for that...didnt notice it