if in a quadratic equation ax^2+bx+c=0 the values of a and c have opposite signs , the solutions of the equation are real numbers
So what's the question?
its a true or false ?
not necessarily true: \[\sqrt{b ^{2}-2ac}\] is positive, then the solutions of the equation are real numbers
so u saying its false
it can be true and it can be false, so the correct answer would be :"not necessarily true"
o unfortunately I just need a t/f only
I hope you get the concept, its what's important, and unless you have an actual expression with real numbers, then one can't simply state t/f,
so its leaning more on the not true side
\[\sqrt{b^2-4ac}\] If a and c have opposite signs, then -4ac is always possitive. b^2 is always positive. So then the whole sqrt is also positive. And that means real solutions. Answer: TRUE
Makes sense?
ya
:D
ok can U help me with this one Compare taking a root and rising to a power. Support your observations with your own examples.
Join our real-time social learning platform and learn together with your friends!