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Mathematics 7 Online
OpenStudy (anonymous):

if in a quadratic equation ax^2+bx+c=0 the values of a and c have opposite signs , the solutions of the equation are real numbers

OpenStudy (anonymous):

So what's the question?

OpenStudy (anonymous):

its a true or false ?

OpenStudy (anonymous):

not necessarily true: \[\sqrt{b ^{2}-2ac}\] is positive, then the solutions of the equation are real numbers

OpenStudy (anonymous):

so u saying its false

OpenStudy (anonymous):

it can be true and it can be false, so the correct answer would be :"not necessarily true"

OpenStudy (anonymous):

o unfortunately I just need a t/f only

OpenStudy (anonymous):

I hope you get the concept, its what's important, and unless you have an actual expression with real numbers, then one can't simply state t/f,

OpenStudy (anonymous):

so its leaning more on the not true side

OpenStudy (anonymous):

\[\sqrt{b^2-4ac}\] If a and c have opposite signs, then -4ac is always possitive. b^2 is always positive. So then the whole sqrt is also positive. And that means real solutions. Answer: TRUE

OpenStudy (anonymous):

Makes sense?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

ok can U help me with this one Compare taking a root and rising to a power. Support your observations with your own examples.

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