Question

Vertices of a parallelogram part 2:

Answer 1

Just need prt b and c

Answer 2

Teh highlighted ones is the ones i need help with.

Answer 3

Idk if this will help.

Answer 4

Do you want me to explain it? Or do you just want the answers?

Answer 5

I wuld liek for you to explain it for me pleez

Answer 6

Okay so in part B when they ask you for the length they are basically telling you to use the distance formula which is\[\sqrt{(x _{2}-x _{1})^{2}+(y _{2}-y _{1})^{2}}\]
Then you just plug in the coordinates they give you. For example to fin the length of WX w(-1,2) and x(4,4) you do this \[D=\sqrt{(-1-4)^{2}+(2-4)^{2}}\] that all equals out to be 5.38.

Answer 7

Do you understand how I plugged in the coordinates into the equation?

Answer 8

yea i did...I basically just didn't know wat formula to use to figure it out so that really helped a lot...thank you so much

Answer 9

You're welcome. (: Now let me figure out part c and I'll explain it to you.

Answer 10

aight ;)

Answer 11

what do you round to when when duin teh square roots and stuff?

Answer 12

Just use the 2 numbers after the decimal. Are all of your side lengths equal??

Answer 13

yes...nd okay

Answer 14

Okay for C i'm going to say because all of the side lengths are equal and because you have 2 pair of equal slopes that the parallelogram is a rhombus.

Answer 15

aight i was thinkin tht.

Answer 16

So WY and XZ are your diagonals. To find the area of a rhombus you do \[d _{1}*d _{2}\div 2\]

Answer 17

To find the perimeter you do 4*s where s is the length of one of your sides. (: Thats it.

Answer 18

so any side?

Answer 19

Yeah, because all of your side lengths should be equal anyways.

Answer 20

okay thnk u so much @tiffybabyy u were a big help ;)

Answer 21

Anytime sweetheart. <3