What is the equation of the line that passes through the point (1, 6) and has a slope of 3? A) y = 3x + 5 B) y = 3x + 3 C) y = 3x - 17 D) y = 3x - 5
y = mx + b
where m = slope and b = y intercept
plug x into one of the equations which one gives you an out put of 6 or y = 6
remember (x,y) so you have x = 1
follow??
im not following /:
slope/gradient of 3 which means m=3 in the general equation of y=mx + c the c= y-intercept
we are also provided with the point of (1,6) and we know m=3 so sub both of these into the general equation of y=mx + c to find c(the y-intercept)
then we can rewrite the whole equation and easily figure out which one it is.
this is a graph of a line y = 3x + 5 if we sub 1 into the x value y = 3(1) + 5 y = 8 thus we have the point x , y (1,8) therefore this equation is not the one we are looking for y = mx + b is just the standard formula of a line b is just the number that occurs when x = 0 so the y intercept looks like this (0,y)
y = mx + b 6 = 3(1) + b All you have to do is solve for b
oh ok!
i understand now, i dont know why i didnt before its quite simple! thanks everyone!!
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