Question

if anybody can help me answer this calcullus problem please, i really need it, especiallly on part c. http://assets.openstudy.com/updates/attachments/501b3855e4b02742c0b290dd-bakkah-1343961200572-question.png

Answer 1

which calc 1 or 2?

Answer 2

calculus grae 12

Answer 3

okay ready?

Answer 4

ye

Answer 5

okay according to what I have read plug in the costs to each of problem sets given

Answer 6

20 and 80

Answer 7

i think i got A and B done exactly as needed, could you help me figure otu exactly what they want for C

Answer 8

all they are asking for you to show why a company should increase or decrease according the values found and for you to explain why?

Answer 9

no the one tht asks to use the linear approximation to fidn the price point that will give the max revenue

Answer 10

how do i solve for that?

Answer 11

let me ask what is the linear value so far?

Answer 12

the linear approximation we got was L(x)= -13.29 +10x

Answer 13

can you show this to me so I can look at?

Answer 14

basically the demand function they ask for in part b is 10((x-1)^4/3 / (x^1/3))

Answer 15

we got the derivative of that which was kind of a lengthy derivative, but once we plugged the value given ($50) that gave us 10

Answer 16

then plugging 50 into the original demand function, we got 486.71

Answer 17

the linear approcimation formula is L(x)= f(a)+f'(a)(x-a)

Answer 18

so we wrote out 486.71+10(p-100)=L(x)
that broke down into the equation i sent you earlier .... -13.29+10x

Answer 19

now c is asking to use that equation to find the price which will give us a max revenue like a place where we wont wanna decrease or increase the price

Answer 20

a place where we wont wanna increase or decrease the price is when E =1, that is the bulk of the information and direction I have on the question

Answer 21

im confused on how it all ties together from there on in