Mathematics
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OpenStudy (vishweshshrimali5):
Please help with the solution of the attached answer of the question.........
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OpenStudy (vishweshshrimali5):
OpenStudy (vishweshshrimali5):
@amistre64
@Ishaan94
@mukushla
@lgbasallote
OpenStudy (lgbasallote):
aww why does it need to be downloaded =_=
OpenStudy (vishweshshrimali5):
Why what happened...... ?
OpenStudy (vishweshshrimali5):
For @lgbasallote
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OpenStudy (vishweshshrimali5):
would that work now ............ :)
OpenStudy (lgbasallote):
...wow... o.O
OpenStudy (vishweshshrimali5):
I want to know how did he get the steps........... FROM TRIGONOMETRY and so on.
OpenStudy (lgbasallote):
no idea
OpenStudy (vishweshshrimali5):
@lgbasallote
iits ok...........
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OpenStudy (amistre64):
i never really know why someone else chooses one method over another ....
OpenStudy (amistre64):
but the method he used seems to be all written down
OpenStudy (vishweshshrimali5):
But I don't know how did he get that 2) part...
OpenStudy (vishweshshrimali5):
@mukushla
OpenStudy (amistre64):
im sure hes using thrms/identites that are proven before this problem arises
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OpenStudy (amistre64):
what is a radius of a circumcircle?
OpenStudy (vishweshshrimali5):
Well I know about what is circumcircle,,,,,,,,
but what is its radius (i mean formula) i am sorry
|dw:1343997843196:dw|
OpenStudy (vishweshshrimali5):
@UnkleRhaukus can u pls help me........
@ParthKohli what about u ?
OpenStudy (anonymous):
u mean this formulas \(AH=2R \cos A\) and \(HD=2R \cos B \cos C\) ?
OpenStudy (vishweshshrimali5):
yes
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OpenStudy (unklerhaukus):
i dont think i can help
OpenStudy (vishweshshrimali5):
Its ok...........
OpenStudy (vishweshshrimali5):
@amistre64 ............... Please help...........
@mukushla ....... u too please.....
OpenStudy (anonymous):
law of sins
\[\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}=2R\]
OpenStudy (vishweshshrimali5):
Ok then ............
P.S. R is the radius of circumcentre right ?
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OpenStudy (anonymous):
yeah|dw:1343998692751:dw|