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Mathematics 15 Online
OpenStudy (vishweshshrimali5):

Please help with the solution of the attached answer of the question.........

OpenStudy (vishweshshrimali5):

OpenStudy (vishweshshrimali5):

@amistre64 @Ishaan94 @mukushla @lgbasallote

OpenStudy (lgbasallote):

aww why does it need to be downloaded =_=

OpenStudy (vishweshshrimali5):

Why what happened...... ?

OpenStudy (vishweshshrimali5):

For @lgbasallote

OpenStudy (vishweshshrimali5):

would that work now ............ :)

OpenStudy (lgbasallote):

...wow... o.O

OpenStudy (vishweshshrimali5):

I want to know how did he get the steps........... FROM TRIGONOMETRY and so on.

OpenStudy (lgbasallote):

no idea

OpenStudy (vishweshshrimali5):

@lgbasallote iits ok...........

OpenStudy (amistre64):

i never really know why someone else chooses one method over another ....

OpenStudy (amistre64):

but the method he used seems to be all written down

OpenStudy (vishweshshrimali5):

But I don't know how did he get that 2) part...

OpenStudy (vishweshshrimali5):

@mukushla

OpenStudy (amistre64):

im sure hes using thrms/identites that are proven before this problem arises

OpenStudy (amistre64):

what is a radius of a circumcircle?

OpenStudy (vishweshshrimali5):

Well I know about what is circumcircle,,,,,,,, but what is its radius (i mean formula) i am sorry |dw:1343997843196:dw|

OpenStudy (vishweshshrimali5):

@UnkleRhaukus can u pls help me........ @ParthKohli what about u ?

OpenStudy (anonymous):

u mean this formulas \(AH=2R \cos A\) and \(HD=2R \cos B \cos C\) ?

OpenStudy (vishweshshrimali5):

yes

OpenStudy (unklerhaukus):

i dont think i can help

OpenStudy (vishweshshrimali5):

Its ok...........

OpenStudy (vishweshshrimali5):

@amistre64 ............... Please help........... @mukushla ....... u too please.....

OpenStudy (anonymous):

law of sins \[\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}=2R\]

OpenStudy (vishweshshrimali5):

Ok then ............ P.S. R is the radius of circumcentre right ?

OpenStudy (anonymous):

yeah|dw:1343998692751:dw|

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