Question

i just need help with the formula here...find the number of ways in which each committee can be selected.
3 people from a group of 5

Answer 1

5C3

Answer 2

the formula would be combinations \[nCr = \frac{n!}{r!(n-r)!}\]
does that help?

Answer 3

so well thats what i did...5!/(2!-3!)...and the answer was wrong

Answer 4

that's because it's \[\frac{5!}{3!2!}\]not minus

Answer 5

5P3
----
3!

Answer 6

5.4.3 5.4
----- = --- = 20/2
3.2.1 2

Answer 7

oo okay oops!...thanks:)