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x^2−5x=160
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x^2−5x-160=0 1st find factors of -160 whosse sum or difference = -5
OMG hehe i'm back LOL uhm uhm i can't think of any
oh btw hot abs XDD
x=2\[\sqrt[3]{4}\]
no i mean two factors of 160 that add up to 5 or -5
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There are no such (whole) numbers, so you're going to have to use the quadratic formula.
\[x=1/2(5\pm \sqrt{665})\]
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