Question

Find domain and range of:

g(x)=sqrt.(16-x^4)

Answer 1

\[g(x)=\sqrt{16-x^4}\]

Answer 2

i believe the Domain is : [-2,2]

Answer 3

including: \[\pm2\]

Answer 4

and I would think the Range is [0,4]

Answer 5

well done @Terra_B

Answer 6

however when i type it into my ti 89 it appears not to hit the x-axis

Answer 7

which makes it look the Range at least is off..

Answer 8

Nope. Your calculator has only so much resolution. Your math is perfect.

Answer 9

i think range can be (-4 ,4)
because root(16-0)=+4 or -4

Answer 10

When a function contains square root, it is assumed by convention to be the principal (positive) root.