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OpenStudy (cwrw238):
you need to factor the top and bottom and see if they will cancel
x^2 - 36 is difference of 2 squares can you factor this?
the rule is
a^2 - b^2 = (a + b)( a - b)
OpenStudy (cwrw238):
in this case a = x and b = 6
OpenStudy (cwrw238):
so what is x^2 - 36 = to?
OpenStudy (anonymous):
i dont knnow
OpenStudy (anonymous):
like (x-6)^2 ?
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OpenStudy (cwrw238):
ok well you need to replace a by x and b by 6 in the formula for a^2 - b^2
a^2 - b^2 = (a + b)(a - b)
so x^2 - 36 = (x + 6)(x - 6)
OpenStudy (anonymous):
ohh, okay
OpenStudy (cwrw238):
right
so how about factors of
x^2 - 12x + 36
- have you had experience of factoring expressions like this?
OpenStudy (anonymous):
x+6/x-6
OpenStudy (cwrw238):
Snap - plz don't just give the answers - it against code of conduct
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OpenStudy (anonymous):
oh sorry
OpenStudy (anonymous):
im terrible at factoring
OpenStudy (cwrw238):
ok - to factor this we need two numbers whose product is + 36 and when added give -12
-6 * -6 = 36 and -6 + (-6) = -12
so factors are (x - 6)(x - 6)