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Mathematics 16 Online
OpenStudy (anonymous):

Graph: y > x-2 y > -2x+1

OpenStudy (anonymous):

wat is it exactly u are trying to do???

OpenStudy (anonymous):

graph liner equalites

OpenStudy (anonymous):

are you sure thats correct ? what are the steps ?

OpenStudy (allank):

I'm backing @asdfghjkl8063 . @breeskee03 , The first thing you do is graph these two linear equations: y =x-2 y =-2x+1 Since the inequalities are all "greater than", and there's no "equal to", you will draw dotted graphs to imply that values along the graph are not part of the solution. Having done that, you introduce the inequalities through shading. Let's begin with y > x-2 . Pick a point on any side of the graph, and plug in that value of x and y into the inequality. for instance, the point (0,0). Plugging those into the inequality, we get 0>-2, which is true. Therefore shade the opposite side of the graph, leaving the unshaded area as the solution area. Do the same for y>-2x+1 to get the final solution area. I hope that helps.

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