Question

HELP PLEASE !!! How do you the next step...? click attached http://bamboodock.wacom.com/doodler/94dc40f3-284a-4f3b-a247-190e08863e47

Answer 1

nah, take Sin2x = y and solve the quadratic equations

Answer 2

how!?? @telltoamit

Answer 3

y^2 + (1 - root3 / 2 ) y - root3 / 2 = 0

Answer 4

so the book said the next step was this...(the red colored ones) @telltoamit

Answer 5

but how did they get sin2x+1...? could you please help me:(?

Answer 6

y^2 + (1 - root3 / 2 ) y - root3 / 2 = 0

(y+1) (y - root3 / 2 ) = 0

(Sin2x +1) (Sin2x - root3 / 2 ) = 0

Answer 7

if i take sin2x = y what would it become?

Answer 8

@telltoamit

Answer 9

i dint understand ur question?

Answer 10

so the first step you did was y^2 + (1 - root3 / 2 ) y - root3 / 2 = 0 why is it y^2??

Answer 11

i made a mistake on that one...but i still dont get why the next step comes like y^2 + (1 - root3 / 2 ) y - root3 / 2 = 0

Answer 12

help me please!!!

Answer 13

Sin2x^2 - root3 / 2 Sin2x + Sin2x - root3 / 2 = 0

Sin2x^2 + (1 - root3 / 2 ) Sin2x - root3 / 2 = 0

y^2 + (1 - root3 / 2 ) y - root3 / 2 = 0

(y+1) (y - root3 / 2 ) = 0

(Sin2x +1) (Sin2x - root3 / 2 ) = 0

Answer 14

okay i got it!! but i want to know the solutions with 0˚≤ x < 360˚ so my first step i did was like this @telltoamit

Answer 15

it might be too late

but, for first one, 2x = 270 or 630

second: 2x = 60, 240, 450, 590

PS: Use ASTC for quadrants