Question

Spencer has to gift wrap all the surfaces of the poster tube shown below.



What is the area of the gift wrapping paper that Spencer will need?

http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0800_Subtest_04_19/image0044e6787b1.jpg

Answer 1

Page is taking a while to load, but it sounds like you want to find the surface area of a cylinder

Answer 2

The surface area of a cylinder is

SA = 2*pi*r^2 + 2*pi*r*h

where r is the radius and h is the height (or length) of the cylinder

Answer 3

Well the radius is 2 and the length is 9. So it would be 2*3.14*2^2+2*3.14*2*9=138.3

Answer 4

I'm getting 138.16

Answer 5

well I got 138.16 but the closest answer on here is 138.3.. i must have done my math wrong somewhere.

Answer 6

hmm wish the page would load (but it's not working)

Answer 7

can you take a screenshot and post it instead?

Answer 8

It looks just like that.

Answer 9

Does it have any thickness to it?

Answer 10

like the tube itself

Answer 11

quick question, is 226.2 a possible answer?

Answer 12

No the only pssible answers are
163.4
113.1
153.4
138.3

Answer 13

ok my guess is that this tube is hollow (and not necessarily a cylinder...but it's similar)

Answer 14

I think what they did was round all the answers but they made a typo and it is suppose to be 138.2 because you can round 138.16 to 138.2

Answer 15

and I'm guessing you only have to wrap the outside of it (and not the inside) oh and the top and bottom aren't included

Answer 16

the lateral surface area is

LSA = 2*pi*r*h

In this case, r = 2 and h = 9, so

LSA = 2*pi*r*h

LSA = 2*pi*2*9

LSA = 113.097335529232

which is roughly 113.1

But the problem with that is that I'm using pi = 3.14159265... and not just pi = 3.14

Answer 17

So you might be right and they might have made a typo somewhere