The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?

Which of the following equations is used in the process of solving this problem?
3n^2 + 5 = 116
3n^2 + 3n + 3 = 116
3n^2 + 6n + 5 = 116

Question

The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?

Which of the following equations is used in the process of solving this problem?
3n^2 + 5 = 116
3n^2 + 3n + 3 = 116
3n^2 + 6n + 5 = 116

anonymous · Answer

3n^2 + 6n + 5 = 116?

kainui · Answer

Well if you say they're 3 consecutive positive integers, we can label them as n, n+1, and n+2. Then we'll square them all and add them together to get:

n^2+(n+1)^2+(n+2)^2=116 and from there you can expand them out and see.

anonymous · Answer

n^2 + n^2+2n+1 + n^2+4n+4

kainui · Answer

Yes, exactly! Now combine the like terms.

lgbasallote · Answer

...which means browniie was right in the first place haha lol

kainui · Answer

@Igbasallote Well I wasn't sure if he had the answers and wanted to understand them or if he was checking, he's not a big talker lol.