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Solve this quadratic equation. x^2 + 5x + 3 = 0
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Hint: Quadratic formula.
\[x = {-b \pm \sqrt{b^2 - 4ac} \over 2a} \]Know what a,b,c are here?
ya
|dw:1344088566727:dw|
Okay. Can you continue? Hint: Use the draw feature.
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@answereverything is right, but he/she shouldn't answer questions.
guess he isnt called "answereverything" for nothing
why is that?
x = 1/2 (sqrt(13)-5)
{x == (-5 + Sqrt[13])/2}
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ya @ParthKohli can you explain the steps?
i need to study so yeah.. thanks:)
Select[Solve[3 + 5 x + x^2 == 0, x], Element[x /. #1, Reals] & ]
What do you get substituting a,b,c in the quadratic formula? @browniesmiths98
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