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Mathematics 30 Online
OpenStudy (anonymous):

Solve this quadratic equation. x^2 + 5x + 3 = 0

Parth (parthkohli):

Hint: Quadratic formula.

Parth (parthkohli):

\[x = {-b \pm \sqrt{b^2 - 4ac} \over 2a} \]Know what a,b,c are here?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

|dw:1344088566727:dw|

Parth (parthkohli):

Okay. Can you continue? Hint: Use the draw feature.

Parth (parthkohli):

@answereverything is right, but he/she shouldn't answer questions.

OpenStudy (lgbasallote):

guess he isnt called "answereverything" for nothing

OpenStudy (anonymous):

why is that?

OpenStudy (anonymous):

x = 1/2 (sqrt(13)-5)

OpenStudy (anonymous):

{x == (-5 + Sqrt[13])/2}

OpenStudy (anonymous):

ya @ParthKohli can you explain the steps?

OpenStudy (anonymous):

i need to study so yeah.. thanks:)

Parth (parthkohli):

Because it is against the code of conduct. http://openstudy.com/code-of-conduct

OpenStudy (anonymous):

Select[Solve[3 + 5 x + x^2 == 0, x], Element[x /. #1, Reals] & ]

Parth (parthkohli):

What do you get substituting a,b,c in the quadratic formula? @browniesmiths98

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