Write an equation of a line in slope intercept form that is parallel to y = 3x+6 and passes through the point (-10, 2.5)
Okay... so if a line is parallel to another line, then the slope of the two lines would be the same.
And if you want to find out the equation of the line, plug in x and y values in the equation. X and Y values are given. In your case, it is (-10, 2.5). Basically, the equation would then be y=3x+b.
the slope intercept form is (y-y1) = m(x-x1) m=3(because the lines are parallel---> same slope plug in the given values of x and y into x1 and y1 and solve for y (so that y is on the left hand side). This would give your answer!
Do you get it? Let me know if you don't.
@benfraser1012 I am confused with the question... If I have to find the equation using slope intercept form.... then slope intercept form is y=mx+c not (y-y1) = m(x-x1)...... Slope would be 3
And now I dont know where to put the points... x1 and y1........
okay. Yes, the slope intercept form would be y=mx+c (like you said) but you don't know what "c" is yet, right. You just know that m=3. So to find out C, you use the formula that i mentioned earlier.
So it would be y-(-10)=3(x-2.5). y+10=3x-7.5 y=3x-17.5
so from this c=-17.5.. right ?
yes.
SO is this the equation y=3x-17.5
Yes. That's your answer.
Okay... now I read the question correctly...... We've to write the equation in slope intercept form using the given data..... So it's quite easy.... just use point-slope form and the convert it into slope intercept form... right ?
You got it!
Yea.. My mistake I read the question carelessly...... Thanku bro..
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