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how would you find the equation of the straight line that is perpendicular to the line 2x+3y-8= 0 at the point (1,2).?
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2(1)+3(2)-8=0 2+6-8=0 8-8=0 0
use the slope-intercept form of a line: y = mx+b and perpendicular lines have opposite reciprocal slopes
start by finding the slope of the given line
the slope of original formula is 2/3 the opposite reciprocal would be -3/2 right? so how would i find b?
you find b or "y-intercept" by plugging the given point (1,2) in for x and y also i think you are off by a negative....slope should be -2/3
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y = mx+b if m=3/2 --> 2 = (3/2)(1) + b solve for b
thank you:)
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