Question

how would you find the equation of the straight line that is perpendicular to the line 2x+3y-8= 0 at the point (1,2).?

Answer 1

2(1)+3(2)-8=0
2+6-8=0
8-8=0
0

Answer 2

use the slope-intercept form of a line: y = mx+b
and perpendicular lines have opposite reciprocal slopes

Answer 3

start by finding the slope of the given line

Answer 4

the slope of original formula is 2/3 the opposite reciprocal would be -3/2 right? so how would i find b?

Answer 5

you find b or "y-intercept" by plugging the given point (1,2) in for x and y

also i think you are off by a negative....slope should be -2/3

Answer 6

y = mx+b
if m=3/2

--> 2 = (3/2)(1) + b
solve for b

Answer 7

thank you:)