Question

[2.07] Solve 3|2x − 1| − 4 = 29 for x. Show your work.

Answer 1

@dpaInc Thamks For Viewing My Question.

Answer 2

np...
do you know what to do first here?...

Answer 3

I'm Not Sure.

Answer 4

let's isolate the absolute value by adding 4 then dividing by 3 to both sides of the equation...

Answer 5

Ok

Answer 6

\(\large 3|2x-1|-4=29 \)
\(\large 3|2x-1|-4\color {red}{+4}=29\color {red}{+4} \)
\(\large 3|2x-1|=33 \)
\(\huge \frac{3|2x-1|}{\color {red} {3}}=\frac{33}{\color {red}{3}} \)
\(\large |2x-1|=11 \)

Answer 7

now that we've isolated the absolute value on one side, we'll need to solve these two equations:
\(\large 2x-1=11 \) OR \(\large 2x-1=-11 \)
can you take it from here?

Answer 8

@Deldrickg are you in FLVS?