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Mathematics 19 Online
OpenStudy (anonymous):

What is the cost of car is mulplied by 0.06 the result is $1780. Find the cost of the car.

OpenStudy (anonymous):

Some help please

OpenStudy (campbell_st):

well its like saying 6% = $1780 find 1% then multiply by 100

OpenStudy (anonymous):

not understanding

OpenStudy (campbell_st):

ok... the cost of the car is 100%... and you know 6% of the cost... so if 6% = $1780 find 1% then multiply by 100 to get 100%

OpenStudy (anonymous):

1x100

OpenStudy (anonymous):

so te cost is 100

OpenStudy (anonymous):

hello

OpenStudy (campbell_st):

no.... if you have 6 items costing $12 what does 1 item cost..?

OpenStudy (campbell_st):

apply the same reasoning to the problem 6% = $1780 find 1%

OpenStudy (anonymous):

not sure

OpenStudy (campbell_st):

did you try the littler problem 6 items cost $12... what does 1 cost..?

OpenStudy (anonymous):

2.00

OpenStudy (campbell_st):

how did you do it...?

OpenStudy (anonymous):

2x6

OpenStudy (campbell_st):

is there another way... using an opposite operation

OpenStudy (anonymous):

not sure

OpenStudy (campbell_st):

ok.... do you know the opposite of multiplication...?

OpenStudy (anonymous):

divide

OpenStudy (campbell_st):

could you use division to solve 6 items cost $12 what is the cost of 1

OpenStudy (anonymous):

so you want me to divide 6 and 12

OpenStudy (campbell_st):

oops 6% = $1780 ..... find 1%

OpenStudy (anonymous):

how do i dothat

OpenStudy (campbell_st):

ok.... I have to go.... good luck with your maths the answer is \[\frac{1780}{6} \times 100\] just calculate it

OpenStudy (anonymous):

how do I calculate mulp 1780x 100

OpenStudy (campbell_st):

do you have a calculator..?

OpenStudy (anonymous):

yes

OpenStudy (campbell_st):

please use it

OpenStudy (anonymous):

well I would if I knew what to do and what figures to put on the calcuator

OpenStudy (anonymous):

178000.

OpenStudy (anonymous):

is that right

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

can you help me or shalli get someoneelse

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