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Mathematics 17 Online
OpenStudy (anonymous):

An identification code is to consist of six letters followed by three digits. How many different codes are possible if repetition is permitted

OpenStudy (anonymous):

Just consider possibilities for each character separately and then multiply them all together.

OpenStudy (anonymous):

i have an answer, just not confident in it. wanted someone to verify

OpenStudy (anonymous):

Yeah, well, show your answer, possibly show your reasoning as well and I'll check it.

OpenStudy (anonymous):

26 *26*26*26*26*26*10*10*10 = 3,087,915,776,000 possible combinations

OpenStudy (anonymous):

i used 26 for the number of alphabets

OpenStudy (anonymous):

Didn't you make a mistake in your calculations? I got a different answer: http://www.wolframalpha.com/input/?i=26%5E6+*+10%5E3

OpenStudy (anonymous):

hmm not sure where i went wrong but thanks, thats exactly why i like to have others look at my work

OpenStudy (anonymous):

Sure, those small mistakes are always the most annoying.

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