hat is the solution to the rational equation (3/2) - (1/x-4) = (-2/2x-8) ?
Hint: \(\large\frac{3}{2} - \frac{1}{x-4} = -\frac{2}{2(x-4)}\)
Cancel the 2/2 on the right side to get \(\large\frac{3}{2} - \frac{1}{x-4} = \frac{1}{x-4}\) Then add 1/(x-4) to both sides to get \(\large\frac{3}{2} = \frac{1}{x-4} + \frac{1}{x-4}\)
You should be able to finish the rest from there
i got 14/3
???
I got 16 in the numerator. Double check your work.
then what would the final answer be , no solution right ?
Why would it be no solution? x = 16/3 How is that no solution?
this is what i have to pick from : No solution x = -4 x = 2 x = 4
Oh...I made a mistake
You should have gotten 3/2 = 0 after adding 1/(x-4) to both sides leaving no solution.
3/2 = 0 cannot be true, therefore no solution.
okay then .
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