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What is the value of 5p1?
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Hint: \[\Large _nP_r = \frac{n!}{(n-r)!}\]
wait what's n and r??
that's the general formula
in this case, n = 5 and r = 1
oh okay thank you!!
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so \[\Large _nP_r = \frac{n!}{(n-r)!}\] becomes \[\Large _5P_1 = \frac{5!}{(5-1)!}\]
Thank you but what does the exclanation ! mean how do you figure that out?
oh sry, i should have clarified
n! = n*(n-1)*...3*2*1 So 5! = 5*4*3*2*1
Basically you start with the given number and you multiply it by every integer smaller than it til you get to 1
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Ok thanks!
you're welcome
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