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Mathematics 13 Online
OpenStudy (anonymous):

Some one please help me! I need help with a question. I did the first two parts now I just need the last part. Part 1: Create and provide the dimensions for two similar figures of your choosing. Part 2: What is the similarity ratio of these figures along with the ratio of their surface area and volume? Part 3: Show your work, either using the actual volumes or using the formula, that the volume ratio is true. 1. Rectangular prisms Figure 1 - L:2 W: 3 H : 1 Figure 2 - L: 4 W: 6 H : 1 2. The similarity ratios is 1:2 because one figure 2 is twice as large as figure 1. 3.

OpenStudy (phi):

shouldn't you also double H for Figure 2 (all dimensions are doubled or it won't be similar)

OpenStudy (anonymous):

oh yes thank you I didnt see that

OpenStudy (anonymous):

ok the height in figure 2 is 2 now

OpenStudy (anonymous):

now i need to find a volume ratio?

OpenStudy (phi):

Part 2: What is the similarity ratio of these figures along with the ratio of their surface area and volume? I would tweak the answer to 2. they want the ratios of the surface area and the ratio of their volumes.

OpenStudy (phi):

the volume is L*W*H so for figure 1: volume is L*W*H for figure 2: 2*L*2*W*2*H the ratio of figure 2 to figure 1 is ?

OpenStudy (anonymous):

Figure 1 = 6 Figure 2 = 48

OpenStudy (phi):

and the ratio is ?

OpenStudy (anonymous):

1:8?

OpenStudy (phi):

6/48 is 1/8 or in general, if two similar figures (in 3D so they have volume), and they have a similarity ratio of k, the volume of the bigger figure will be k^3 (k cubed) bigger. btw, when you say The similarity ratios is 1:2 because one figure 2 is twice as large as figure 1. I would change figure 2 is twice as large as figure 1. because figure 2's volume is 8 times bigger than figure 1. It is better to say that each dimension of figure 2 is twice as large as figure 1. and surface area scales as k^2 (k squared) so you should add to the answer for 2. ratio of figure 2 area to figure 1 area is 2^2 =4 ratio of figure 2 volume to figure 1 volume is 2^3 =8

OpenStudy (phi):

you just did 3. or you could use the formula: \[ \text{Volume ratio = }\frac{k*L*k*W*k*H}{L*W*H}= k*k*k= k^3 \]

OpenStudy (anonymous):

wait whats the work for 3?

OpenStudy (phi):

Part 3: Show your work, either using the actual volumes that is what you did when you found 6 and 48 they want you to show that the volume ratio (big to small) is 2^3 = 8 and 48/6= 8

OpenStudy (anonymous):

thank you

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