Question

Evaluate 8x^–2y^0 for x = 2 and y = –4.

Answer 1

Replace x with 2 and y with -4. Then evaluate

8x^(-2)y^0

8(2)^(-2)*(-4)^0

8(1/(2^2))*(1)

8*(1/4)*1

8/4

2

So 8x^(-2)y^0 = 2 when x = 2 and y = 0

Answer 2

thanks neither me or my dad could figure that one out! lol

Answer 3

np