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evaluate exponential expression.. 5^3 x 5^5
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When multiplying exponential expressions, you add the exponents \[\Large 5^3 \times 5^5 = 5^{3+5}\]
2^-3 x 2 ?
2 = 2^1 Add the exponents and use the idea that \[\Large x^{-k} = \frac{1}{x^k}\] where k is some positive number
Ex: \[\Large 5^{-3} = \frac{1}{5^3}\]
so 1/2^3 x 2^1 ..now how do you solve?
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rewrite 2^1 as (2^1)/1 and then multiply straight across so 1*2^1 = 2 and 2^3 * 1 = 2^3 or 8 So you get 2/8 which reduces to 1/4
so would 7^6 x 7^7 = 1/7?
No, add the exponents
what do you get
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