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solve x^2+4x+4=-28
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easiest way to ,solve it is to factorise on the left hand side. the solve for x. You'll end up with 2 complex roots to the question...
There's a few ways to solve...i'll show you how to complete the square... You have to first get the constant to one side. x^2+4x=-32 Then you take the coefficient of 4 and divide by 2. then square that; x^2+4x+4=-28 (x+2)^2=-28
wait...did you need x?
the alternative is to add 28 to both sides and use the general quadratic formula... but again, you'll end up with 2 complex roots
it says solve using any method
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I came up with x^2+4x+28=0
Good, now use the quadratic formula, completing the square, or factor!!
|dw:1344321831991:dw| is this what you are talking about?
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