solve x^2+4x+4=-28

Question

solve x^2+4x+4=-28

campbell_st · Answer

easiest way to ,solve it is to factorise on the left hand side. 

the solve for x. 

You'll end up with 2 complex roots to the question...

anonymous · Answer

There's a few ways to solve...i'll show you how to complete the square...
You have to first get the constant to one side.
x^2+4x=-32
Then you take the coefficient of 4 and divide by 2. then square that;
x^2+4x+4=-28
(x+2)^2=-28

anonymous · Answer

wait...did you need x?

campbell_st · Answer

the alternative is to add 28 to both sides and use the general quadratic formula... 

but again, you'll end up with 2 complex roots

anonymous · Answer

it says solve using any method

anonymous · Answer

I came up with x^2+4x+28=0

anonymous · Answer

Good, now use the quadratic formula, completing the square, or factor!!

anonymous · Answer

|dw:1344321831991:dw| is this what you are talking about?