Solve for x: 3|x − 3| + 2 = 14 No solutions x = −1, x = 8.3 x = 0, x = 7 x = −1, x = 7
Please Help!
Where are you stuck?
i got x = 5 and that isn't one of my options i did: 3|x − 3| + 2 = 14 - 2 -2 3|x − 3| = 12 +3 +3 3|x| = 15 3/3|x| = 15/3 |x| = 5
no you are suppose to divide by 3
3|x − 3| = 12 |x − 3| = 12/3 |x − 3| = 4
Ah. Try looking at it like this: 3*(|x-3|)+2=14 note: absolute value bars act like parentheses (the above is redundant but underlines the point)
x − 3 = 4 and -x+3=4
so its x = 7? right
those are the two equations you need to solve
yeah that's one of the answers. what's the other one?
x = -1 or 1?
-x+3=4 solve that
just trial and error the 4 options to see what fits ....
Don't ever do trial an error. A waste of time in tests
-x + 3 = 4 -3 -3 -x = -1 x = 1?
well, 3 are trialable :)
-x + 3 = 4 -3 -3 -x = 1 x = -1?
trial and error is perfect for tests; take an answer optionand see if it fits, if not; youve narrowed it down
you got the signs wrong.
then you want the person to guess?
no, i want the person to "dbl chk" the answer options
ohh okay i see where i made the mistake so the answer would be: x = −1, x = 7
correct "brohoof"
can you help me with 2 more?
Ok post another question.
How many solutions does the equation 2|x − 3| + 4 = 4 have? Zero One Two Infinitely Many
What if you get a question that doesn't have multiple choice options
3|x − 3| + 2 = 14 does x=0 work? 3|−3| + 2 = 14 9 + 2 = 14 no does x=7 work? 3|7 − 3| + 2 = 14 12 + 2 = 14 yes does x=-1 work? 3|-1 − 3| + 2 = 14 12 + 2 = 14 yes
if the question has no "options" then waste the time doing it the long way :)
\[2|x − 3| + 4 = 4 \\ 2|x − 3| + 4-4 = 4-4\\ 2|x − 3| = 0 \\|x − 3| = 0/2 \\ |x − 3| = 0 \]
two equations means two what?
2|x − 3| + 4 = 4 - 4 -4 2|x − 3| = 0 /2 /2 |x-3| = 0 + 3 +3 |x| = 3?
nice shorthand .... reminds me of someone i know :)
sp their are two solutions right?
well the two solutions you get are the same.....
so I guess it's just one.
ok well last question?
huh? me short hand? what are you talking about?
ok
Solve 3|2x + 2| − 7 = 5 for x.
\[3|2x + 2| − 7 = 5\\ 3|2x + 2| − 7+7 = 5 +7\\3|2x + 2| = 12\\ |2x + 2| = 12/3\\|2x + 2| = 4\]
the two equations are then 2x+2=4 and -2x-2=4
solve each equation for x.
3|2x + 2| − 7 = 5 +7 +7 3|2x + 2| = 12 /3 /3 |2x + 2| = 4 -2 -2 |2x| = 2 /2 /2 |x| = 1?
|2x + 2| = 4 from this step that you did you have to split it into two equations.
You can't just subtract 2 from inside the absolute value
x = -1 x = 1 right?
oh then what do i do?
|2x + 2| = 4 turns into 2x + 2 = 4 and -2x - 2 = 4
you have two equations now. Solve x for each one
x = 1 x = -1
no dude you have to solve for each equation 2x + 2 = 4 and -2x - 2 = 4
i did! and thats what i get
x = -3 x = 1
how about that?
please help @RyanL.
you are right
Really? Okay well thank you soo much!(: im glad you actually helped me out and not just gave me the answer(:
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