Question

find x-values that makes f(x)>0 for:
f(x)=x(x+1)(x-2)^2

Answer 1

Hint: Since f(x) = x(x+1)(x-2)^2 set

x(x+1)(x-2)^2 > 0

Solve for x

Answer 2

Or just consider
x(x+1)(x-2)(x-2)
If all terms are > 0, or 2 terms are > 0, or none of the terms is > 0, the result is > 0

Answer 3

from negative infinity to -1 union from 0 to infinity ==> the values of x

Answer 4

sana dont do like this

Answer 5

:(

Answer 6

:(

Answer 7

so the answer is (-∞, -1) U (0, ∞)?

Answer 8

yes