Question

Please see attachment ..

Answer 1

Help!!!

Answer 2

well i know that:

a:b :: c:d

that is
a*d = b*c

Answer 3

multiply 2 sides of equation by \(a\) then simplify see what happens

Answer 4

b+c+{(a-c)(a-b)/a}
first add these two

Answer 5

What do you get?

Answer 6

Ok wait

Answer 7

well you meant like this?:

\[\large{a(a+d)=a(b+c+\frac{(a-b)(a-c)}{a})}\]
\[\large{a^2+ad=ab+ac+(a-b)(a-c)}\]

Answer 8

mukushla is not typing a reply… whats the problem with site?

Answer 9

In proof you should start with any one side and reach the other side

Answer 10

\[\large{a^2+ad=ab+ac+a^2-ac-ab+bc}\]
\[\large{a^2+ad=a^2+bc}\]

@mukushla I also dont know .. and it is showing you offline

Answer 11

well ad=bc and we are done

Answer 12

off topic attachment sorry

Answer 13

Oh yes right @mukushla thanks a lot

Answer 14

yw....:)