Question

steps to solving :
3x-4y-4z=8
4x+2y-2z=11
-5x+8y+3y=-9

Answer 1

1st eq + 2(2nd eq)
2(1st eq) + 3rd eq

Answer 2

ok i thought it was 4(1st eq) + -3(2nd eq)
then, 5(2nd eq) + 4(3rd eq)

Answer 3

that would also work

Answer 4

what i posted would eliminate y
what u posted would eliminate x

Answer 5

i try it ddnt get the right answer i checked my work and i dont see any mistakes and yes i was tryin to solve for y and z first and then find x . I got y = 0

Answer 6

which way do u wanna go? yours or mine?

Answer 7

I'm tryin yours right now to see what i get.

Answer 8

ok let's see

1st eq + 2*(2nd eq) 3x-4y-4z=8
8x+4y-4z=22
-------------
11x-8z=30

2*(1st eq) + 3rd eq 6x-8y-8z=16
-5x+8y+3y=-9
---------------
x-5z=7

Answer 9

yes thats what i got so far

Answer 10

so x=7+5z then
11(7+5z)-8z=30
77+55z-8z=30
47z=-47
z=-1

x=7+5(-1)=2

3(2)-4y-4(-1)=8
6-4y+4=8
-4y=-2
y=1/2

Answer 11

did u get the same?

Answer 12

yes i did and i got x=2 after pluging y and z in is that correct?

Answer 13

look at what i did.
u should get first either x and z, or z and x, and then y

Answer 14

Yes, i solved for x and z and then solved for y , i know understand how the process in this goes, thanks.

Answer 15

u r welcome