Question

Solve 3 + sin2x = 1 - 6sin2x graphically over the domain 0 ≤ x < 2π.

I'm not too sure about how I should start looking at this... am I able to change it to 2 + 7sin2x = 0 ? If so, what would I do next? Thanks.

Answer 1

if it really means graphically then i guess you should graph \(7\sin(2x)+2\) and see where it crosses the \(x\) axis

Answer 2

you want \[7\sin(2x)+2=0\]
\[7\sin(2x)=-2\]
\[\sin(2x)=-\frac{2}{7}\]
take the inverse sine and divide by 2
but just graph if

Answer 3

Thank you! "Solve graphically..." yes, not sure why I didn't graph it, but thanks for explaining as well.