Solve 3 + sin2x = 1 - 6sin2x graphically over the domain 0 ≤ x

Question

Solve 3 + sin2x = 1 - 6sin2x graphically over the domain 0 ≤ x < 2π. 

I'm not too sure about how I should start looking at this... am I able to change it to 2 + 7sin2x = 0 ? If so, what would I do next? Thanks.

anonymous · Answer

if it really means graphically then i guess you should graph $7\sin(2x)+2$ and see where it crosses the $x$ axis

anonymous · Answer

you want $$7\sin(2x)+2=0$$
$$7\sin(2x)=-2$$
$$\sin(2x)=-\frac{2}{7}$$
take the inverse sine and divide by 2
but just graph if

nikolas · Answer

Thank you! "Solve graphically..." yes, not sure why I didn't graph it, but thanks for explaining as well.