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Calculate the unknown side x for each triangle below. 3^2+x^2=6^2 a. b.
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\[b^2=c^2-a^2\]
just substitute b with x
then look for the value of b
@panlac01 let me draw the pic for U
are we talking about a right triangle here?
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|dw:1344491438386:dw|
okay, use the pythagorean theorem
\[a^2+b^2=c^2\]
let 6 be the a, 3 be the b and x be the c
are you sure? according to the equation, the hypotenuse of triangle should be 6
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@dumbcow and @panlac01 so is it 3^2+x^2=6^2 or 6^2+3^2=x^2
the latter
if we followed your drawing then it is the latter
According to your drawing: \[\color{red}{x^2 = 6^2 + 3^2}\]
@panlac01 ok so I got 45-x^2=0
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