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Mathematics 21 Online
OpenStudy (anonymous):

Base your answer to the question on the diagram shown below. What is the probability of drawing a red card, not replacing it, and then drawing another red card?

OpenStudy (anonymous):

OpenStudy (anonymous):

4/25?

OpenStudy (anonymous):

For first red card: \[P(Red) = \frac{2}{5}\]

OpenStudy (anonymous):

Now you did not replace it: So there are 4 cards left and out of which one is red: \[P(Second \;\; Red) = \frac{1}{4}\] What do you get when you multiply them ??

OpenStudy (anonymous):

0.1

OpenStudy (anonymous):

Or \(\frac{1}{10}\)..

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