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Mathematics 16 Online
OpenStudy (anonymous):

HELP! Factor x^2-6x-16 ?

OpenStudy (lgbasallote):

hint: \[x^2 - 6x - 16\] \[\implies x^2 - 8x + 2x - 16\] does that help?

OpenStudy (jiteshmeghwal9):

Hint: Break the middle term such as u get the product of them as 16x^2 & sum as -6x

OpenStudy (anonymous):

What two numbers when you multiply them you get -16 When you add these numbers you get -6

OpenStudy (jiteshmeghwal9):

yes!

OpenStudy (jiteshmeghwal9):

look @lgbasallote reply

OpenStudy (anonymous):

In @Igbasallote Do I Add Or Subtract 8x & 2x ?

OpenStudy (lgbasallote):

you factor out

OpenStudy (lgbasallote):

if you combine them you'll just get back to the original question

OpenStudy (jiteshmeghwal9):

it depends on the question if u can gt it through subtraction then u should do subtraction otherwise add

OpenStudy (anonymous):

Im Sorry But How Do You Factor Out?

OpenStudy (anonymous):

I Got x^2-7x-16 ?

OpenStudy (lgbasallote):

okay... 1) you shouldnt combine...like i said... 2) you should get x^2 - 6x - 16..the same as the problem

OpenStudy (anonymous):

@Igbasallote Oh Ok Umm What Do I Do After That?.

OpenStudy (lgbasallote):

factor out

OpenStudy (lgbasallote):

\[(x^2 - 8x) + (2x - 16)\]

OpenStudy (anonymous):

How Do I Do That?.

OpenStudy (lgbasallote):

factor out the common factor in each parenthesis

OpenStudy (lgbasallote):

for example... the common factor for x^2 + 5x is x(x+5) and the common factor for 3x - 9 is 3(x-3) does that help?

OpenStudy (lgbasallote):

anyway...i gotta log off now so i hope someone can continue this...

OpenStudy (anonymous):

Awwe Ok Thanks For Your Help

OpenStudy (anonymous):

I Got x(x+8) + 2(x-8) ?

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