Write the equation of the line that is perpendicular to the line y =3/2 x + 4 and passes through the point (−6, 3).
y =3/2 x − 1

y =3/2 x + 3

y = −2/3x − 1

y = −2/3x + 3

Question

Write the equation of the line that is perpendicular to the line y =3/2 x + 4 and passes through the point (−6, 3). 
 y =3/2 x − 1 

 y =3/2 x + 3 

 y = −2/3x − 1 

 y = −2/3x + 3

anonymous · Answer

y =3/2 x + 4 

Perpendicular lines have negative reciprocal slope. So first you need to find the slope of the line that I wrote above and then find the negative reciprocal of it.

anonymous · Answer

After that you use point slope form to find the equation you want
$$y-y_a=m(x-x_a)\m=slope\(x_a,y_a)=(−6, 3)$$